Problem Links:
poj2575, uva10038,Problem:
Problem E: Jolly Jumpers
1 4 2 3is a jolly jumper, because the absolutes differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.
Input
Each line of input contains an integer n <= 3000 followed by n integers representing the sequence.Output
For each line of input, generate a line of output saying "Jolly" or "Not jolly".Sample Input
4 1 4 2 3 5 1 4 2 -1 6
Sample Output
Jolly Not jolly
Solution:
Data structure: sets;Source Code:
//Mon Mar 14 01:04:00 CDT 2011#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <ctime>
using namespace std;
int main(int argc, char* argv[])
{
//freopen("input.in", "r", stdin);
//freopen("output.out", "w", stdout);
int N;
while (cin >> N)
{
vector<int> v(N, 0);
set<int> diff;
set<int>::iterator it;
for (int i = 0; i < N; i++)
cin >> v[i];
for (int i = 1; i < N; i++)
diff.insert(abs(v[i] - v[i - 1]));
if ((int) diff.size() != N - 1)
{
cout << "Not jolly" << endl;
continue;
}
int count = 1;
bool flag = true;
for (it = diff.begin(); it != diff.end(); it++, count++)
{
if ((int) (*it) != count)
{
flag = false;
break;
}
}
if (flag && count == N)
cout << "Jolly" << endl;
else
cout << "Not jolly" << endl;
}
//fclose(stdin);
//fclose(stdout);
return 0;
}
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